will this work / burn out output pin?

I am trying to toggle a set of LEDs. I have two pins left available to use, but I would really rather not use both for this one feature if I can help it. I'd like to have a spare pin left over in case I need it later. What I am trying to do is to drive the MSP output positive to select one set of LEDs and negative to select the other set. Will this work without burning out the output pin? Or will the MSP even be able to pull the PNP base to ground far enough to turn it on? Usually, when switching PNP transistors with 12v on the emitter, I typically switch an NPN with the MSP and use that to bring the base to ground, but obviously (or so it seems to me anyway) I can't do that in this situation.

Thanks as usual :)